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Chemical Equilibrium [Sep. 7th, 2011|12:36 pm]
Chemistry Help
Hey it's me again! I have a question about chemical equilibrium.

At temperatures near 400 C, the Kp value for the synthesis of ammonia is 2.5 x 10-4. At 400 C, what would be the approximate value of K for the following reaction?

3H2(g) + N2 (g)⇔ 2NH3 (g)

So, the equation for the partial pressure is Kp = Kc(RT)Δn

Δn-2-4= -2

To solve for Kc, it's Kc= Kp/RTΔn

so it's Kc= 2.5 x 10-4 / (0.821 L atm/Kmol x 673.15 K)-2

Only I get a different answer than what's in the book.

Can anyone tell me where I went wrong? Thanks!

[User Picture]From: my_wits_end
2011-09-08 01:45 am (UTC)
The ideal gas constant is 0.0821 Latm/Kmol.
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From: hoseaesoka
2011-10-31 04:21 pm (UTC)
Sorry for my bad english. Thank you so much for your good post. Your post helped me in my college assignment, If you can provide me more details please email me.

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