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Reaction Rates [Aug. 19th, 2011|04:08 pm]
Chemistry Help
chemistryhelp
[jinx24]
Hey, I was wondering if anyone could help me with a problem regarding reaction rates



For the following reaction in a 4.00-L container, it was found that 1.00 x 10-4 mol of C4H8 reacted over a time period from 10:58 A.M. to 11:15 A.M.

C4H8 (g) --> 2C2H4 (g)

What is the average rate, in M/s, for this reaction?

I took the time period of 10:58-11:15, which is 17 minutes, and did dimensional analysis to figure out what it was in seconds (1020 s). I set the equation up as

1.00 x 10-4 M
--------------
1020 s

and got 9.8 x 10-8 but the answer is 2.5 x 10-8. I don't know what I'm doing wrong.



Thank you to anyone that can help!
linkReply

Comments:
[User Picture]From: lurel
2011-08-19 08:29 pm (UTC)
There's some error in your math. If you divide 1.00 x 10^-4 mol by 4.00 L to get the molarity, you should get 0.000025 M. Then, 0.000025 M divided by 1020 s should result in 2.45 x 10^-8.

Hope that helps.
(Reply) (Thread)
From: jinx24
2011-08-19 10:19 pm (UTC)
Ooooh, I see what I did wrong now.

Thanks !!
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